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3m^2-21m^2+30m=0
We add all the numbers together, and all the variables
-18m^2+30m=0
a = -18; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-18)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-18}=\frac{-60}{-36} =1+2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-18}=\frac{0}{-36} =0 $
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